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Problem Solving :: RE: Smallest positive factor PS. Help.

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Author: Anurag@Gurome
Posted: Wed Dec 26, 2012 12:25 am (GMT -8)

Please check your source.
I think the original question is as follows...

Quote:
Both 5^2 and 3^3 are factors of n × 2^5 × 6^2 × 7^3 where n is a positive integer. What is the smallest possible positive value of n?
Say, N = n × 2^5 × 6^2 × 7^3

If 5^2 and 3^3 are factors of N, then N must contain two 5s and three 3s.

Now, 2^5 × 6^2 × 7^3 does not contain any 5. But it does contain two 3s in 6^2 = (2*3)^2

Hence, the missing two 5s and one 3 must be a factor of n.
Hence, minimum possible value of n is (5^2)*3 = 3*25 = 75

The correct answer is D.

PS : According to the question you have posted, following the similar logic the minimum possible value of n should be 33*(52/2) = 33*26
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